What is the equation of the blue line ?
Csc 2 Cot 2. Replace the with based on the identity. Solving the quadratic we get roots −1± 5.
Web and tan2x + csc2x = sin2x cos2x + 1 sin2x = sin4x + cos2x cos2xsin2x. Spinning the unit circle (evaluating trig. Replace the with based on the identity. Web verify the identity (csc(x)^2)/(cot(x))=csc(x)sec(x) step 1. Web use csc2 x = 1+ cot2x. Take the inverse cosecant of both sides of the equation to extract θ θ from inside the cosecant. Factor using the perfect square. That gives cot2x+2cotx = 4. Now there are various ways to see it. Convert to sines and cosines.
Spinning the unit circle (evaluating trig. Take the inverse cosecant of both sides of the equation to extract θ θ from inside the cosecant. And these are equal if cos4x + sin2x = sin4x + cos2x. Web and tan2x + csc2x = sin2x cos2x + 1 sin2x = sin4x + cos2x cos2xsin2x. Web verify the identity (csc(x)^2)/(cot(x))=csc(x)sec(x) step 1. Convert to sines and cosines. Start on the left side. Replace the with based on the identity. Solving the quadratic we get roots −1± 5. Derivatives of csc, sec and cot functions. That gives cot2x+2cotx = 4.
