Solved 0 CH3 H2SO4 Treating 2methyl1butene with methanol
1 Bromo 1 Methylcyclohexane. Web view the full answer transcribed image text: The alkyl bromide is tertiary.
Solved 0 CH3 H2SO4 Treating 2methyl1butene with methanol
Predict the products of this reaction,. The alkyl bromide is tertiary. Thus, dehydrohalogenation of this compound gives only one alkene. One ether and two alkenes. Web view the full answer transcribed image text: The first set of conditions favors the e2 process, because sodium ethoxide is a strong base.two elimination products are.
Thus, dehydrohalogenation of this compound gives only one alkene. Web view the full answer transcribed image text: Predict the products of this reaction,. The first set of conditions favors the e2 process, because sodium ethoxide is a strong base.two elimination products are. The alkyl bromide is tertiary. Thus, dehydrohalogenation of this compound gives only one alkene. One ether and two alkenes.
